How to add days in sql

how to add days in sql

My requirements

Required. The time/date interval to add. Can be one of the following values: year, yyyy, yy = Year; quarter, qq, q = Quarter; month, mm, m = month; dayofyear, dy, y = Day of the year; day, dd, d = Day; week, ww, wk = Week; weekday, dw, w = Weekday; hour, hh = hour; minute, mi, n = Minute; second, ss, s = Second; millisecond, ms = Millisecond; number: Required. Add Days in Date in SQL. DECLARE @NEWDOB DATE=null SET @NEWDOB= (SELECT DOB, DATEADD(dd,45,DOB)AS NEWDOB FROM tbl_Employees).

Join Stack Overflow to learn, share knowledge, and build your career. Connect and share knowledge within a single location that is structured and easy to search. I am trying to add days to the current date and it's working fine but when I add days to the current date it gives me wrong value. There is no need to use dateadd function for adding or subtracting days from a given date. For adding years, months, hours you need hpw dateadd function. I just ran the query and checked:. From the SQL Ho official documentation :.

BTW - did you mean 11April or 04Nov in your original post? So you would get These two are syntatic sugar exacly the same. This is what you dys, I should think. Almost every fourth year has 29Feb. Subtle, ah? Stack Overflow for Teams — Collaborate and share knowledge with a private group. Create a free Team What is Teams? Learn more. How to add days to the current date? Ask Question. Asked 7 years ago.

Active 4 months ago. Viewed k times. Now is my code: select dateadd dd,getdate. Improve this question. Dherik Fazil Mir Fazil Mir 1 1 gold badge 8 8 silver badges 20 20 bronze badges. Correct would be and indeed i get this result. But you can add a year instead of days: select dateadd year,1,getdate — Tim Schmelter Apr 11 '14 at But i am not getting this dad. Show 2 more comments. Active Oldest Votes.

Improve this answer. Shell 6, 9 9 gold badges 34 34 silver badges 66 rays bronze badges. Shahid Mustafa Shahid Mustafa 4 4 silver badges 3 3 bronze badges. Poor code as it is not explicit. Ad a comment. Jeff Mahantesh Mahantesh 3 3 silver badges 12 12 bronze badges. Dale K TheChanger TheChanger 1 1 silver badge 3 3 bronze badges. Dherik Dherik Asifuzzaman Redoy Ohw Redoy 1, 1 1 gold badge 9 9 silver badges 26 26 bronze badges.

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This will give total number how to walk away from a relationship gracefully days including today in the sdd month. Code Code 3 3 silver badges 8 8 bronze badges. Sign up or log in Sign up using Google. Sign up using Facebook. Sign up using Email and Password. Post as a guest Name. Email Required, but never shown. The Overflow Blog. Podcast Non-fungible Talking. Featured on Meta.

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SQL Server DATEADD() Function

To change a date and/or time by adding a specific number of a chosen unit of time, use SQL Server’s DATEADD() function. This function works on date, time, or date and time data types. It takes three arguments: The desired unit of date/time to add. In our example, it is day; we want to add days to the date. How many units to add. Sep 29,  · How to use the DATEADD () Function and Examples. Add 30 days to a date SELECT DATEADD (DD,30,@Date) Add 3 hours to a date SELECT DATEADD (HOUR,-3,@Date) Subtract 90 minutes from date SELECT DATEADD (MINUTE,,@Date) Check out the chart to get a list of all Author: Tim Cullen. The DATE_ADD () function adds a time/date interval to a date and then returns the date.

Join Stack Overflow to learn, share knowledge, and build your career. Connect and share knowledge within a single location that is structured and easy to search. I have seen a number of postings regarding how to create an SQL Server function that will add a given number of working days to a date. But, none of them calculate exactly the way I need. We have a function that is currently done in code but that I want to move to a native SQL Server function for use by stored procedures and in queries.

We give our customers 5 working days to collect cargo before we start assessing storage charges. The 5 working days exclude weekends and holidays we have a table with the holiday dates.

The trick here is that I need to get the date immediately after the 5 working days regardless of whether it is a weekend or holiday. So I need the function to return the last working date, NOT the first working day after. So, for example:. The 5 working days is the current allotment, but this may change in the future so the number of working days needs to be a parameter. Also, the function may be used over fairly large datasets so I would prefer doing this without loops.

We are running SQL Server Edit: This is not a duplicate of " Add business days to date in SQL without loops " as they want the ending date to be a working day. I want my ending date to be whatever date immediately follows the last grace day ie: 5 working days Mon to Fri I want the Sat date returned, NOT the following Mon.

Unless you have long holidays, 10 days should be enough to find the 5th next working day. Increase it if you need to. If you need a larger number of business days from a date, you can use this which will cater for a year or three. This is their post, I just added holidays to the function This assumes you have a table "tblHolidays" with a datetime field "HolDate". For newbies, there is a test script at the end. Happy Coding! I had a similar requirement earlier so sharing following function which returns new date after adding given no of days only working days to given date , it also gives option to exclude saturday from weekend.

Note: if StartDate falls in weekend, the function above does not consider changing StartDate to next working date. Stack Overflow for Teams — Collaborate and share knowledge with a private group. Create a free Team What is Teams? Learn more. Asked 8 years, 6 months ago. Active 4 years, 2 months ago. Viewed 15k times. Improve this question. Caynadian Caynadian 1 1 gold badge 12 12 silver badges 32 32 bronze badges.

Add a comment. Active Oldest Votes. Improve this answer. That doesn't appear to work? Plugging in a date of October 20th returns a date of October 25th instead of the 26th. Likewise, plugging in the 23rd returns the 28th instead of the 29th. That works really well now, thanks! The only question I have is what happens if the working days is more than 5?

I tried plugging 10 days in instead and got a NULL result. The row that contains number ? Add more to it, say until That's not ideal as it means remembering to change the function if they increase the grace days but its the best solution I've come across. I'll just put in 1 through 31 and hope that economic times dictate less free days instead of more. I am trying to get this to work and so far it has been perfect.

However, I have use cases where my SLA level is like 35 business days. Any thoughts? Show 1 more comment. Dan B Dan B 1, 21 21 silver badges 30 30 bronze badges. Imran Rizvi Imran Rizvi 6, 10 10 gold badges 52 52 silver badges 93 93 bronze badges. Nice solution - maybe not as thorough as some of the other options out there but when the precision isn't that important the fewer lines of code make it attractive.

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